Praveen’s Journal

October 22, 2005

Puzzle of the week - Week #42

Filed under: Puzzles — Praveen Kumar @ 7:03 pm

The distance between Station Atena and Station Barcena is 90 miles. A train starts from Atena towards Barcena. A bird starts at the same time from Barcena straight towards the moving train. On reaching the train, it instantaneously turns back and returns to Barcena. The bird makes these journeys from Barcena to the train and back to Barcena continuously till the train reaches Barcena. The bird finally returns to Barcena and rests. Calculate the total distance in miles the bird travels in the following two cases:

(a) the bird flies at 80 miles per hour and the speed of the train is 60 miles per hour

(b) the bird flies at 60 miles per hour and the speed of the train is 80 miles per hour

1 Comment »

  1. Solution:

    Case (a): Bird flies at a speed greater than that of the train

    The train (at a speed of 60 miles per hour) travels 60 miles in 60 minutes. Therefore, the train travels from Atena to Barcena (90 miles) in 90 minutes.

    Importantly, the bird makes the journeys continuously back and forth for this same amount of time (namely, 90 minutes). Thus, the total distance traveled by the bird = 90 miles per hour x 90 minutes = 90 x 90 / 60 miles = 135 miles.

    Case (b): Bird flies at a speed less than that of the train

    In 36 minutes, the bird travels 36 miles, the train travels 54 miles, and the two meet. Now, the train (which is traveling at a speed greater than that of the bird) will reach Barcena before the bird. So, the bird simply returns to Barcena (a return journey of 36 miles). Thus, the total distance traveled by the bird is 72 miles.

    Comment by praveen — October 29, 2005 @ 1:52 am

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